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1115.Quadrant in python

This is the solution of this problem in python:

M=list()
N=list()
pcount=0
count=1000
for i in range(0,count):
    r,s=input().split()
    M.append(r)
    N.append(s)
    x=int(M[i])
    y=int(N[i])
    if(x==0 or y==0):
        break
    else:
        pcount+=1
       
for j in range(0,pcount):
    a=int(M[j])
    b=int(N[j])
    if(a>0 and b>0):
        print("primeiro")
    elif(a>0 and b<0):
        print("quarto")
    elif(a<0 and b<0):
        print("terceiro")
    elif(a<0 and b>0):
        print("segundo")
   

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