1079.Weighted avarages in python

Unknown July 22, 2018 1

This is the solution of this problem in python:

N= int(input())
result=list()
for i in range(0,N):
    x,y,z=input().split()
    x=float(x)
    y=float(y)
    z=float(z)
    avarage=(((x*2)+(y*3)+(z*5))/10)
    result.append(avarage)
for i in range(0,N):
    print("%.1f"%result[i])

1 comment:

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